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IBM Programming with IBM Enterprise PL/I Sample Questions:

1. CORRECT TEXT
Given the following program, the compiler will produce the warning message "The structure member A2 is declared without any data attributes. A level number may be incorrect".
What is the best way to correct the program?
TEST: PROC OPTIONS(MAIN);
DCL
1A,
3A1 FIXED BIN(31),
3 A2,
3 A3 FIXED BIN(31),
3 A4 FIXED BIN(31);
END;

A) Change the level numbers on the declares for A3 and A4 to 4
B) Change the level number on the declare for A2 to 2
C) Change the level number on the declare for A3 to 4
D) Add the attribute CHAR(8) to the declare for A2

2. CORRECT TEXT
If the physical dataset referred to by DDIN has a record length of 200 and a RECFM of F, what happens after executing the following code?
DCL DDIN FILE RECORD INPUT;
DCL P PTR;
DCL 1 INSTR BASED(P),
2 A CHAR(100),
2 B CHAR(100);
ALLOCATE INSTR;
OPEN FILE(DDIN);
READ FILE(DDIN) INTO(INSTR);

A) READ INTO cannot be used on a BASED structure.
B) Program will abend because P has not been properly initialized.
C) One record
will be read into the structure INSTR.
D) One record will be read into the buffer and the pointer will be set accordingly.

3. CORRECT TEXT
Given the following piece of code, which loop construct using WHILE or UNTIL will give identical output?
DCLI FIXED BIN (31);
DO I = 10 TO 1 BY - 1;
PUT (I);
END;

A) 1= 10;
DO UNTIL (I < 1);
PUT (I);
I = I - 1;
END;
B) 1= 10;
DO UNTIL (I> 1);
PUT (I);
I = I - 1;
END;
C) I = 10;
DO WHILE (I> 1);
PUT (I);
I = I - 1;
END;
D) 1= 10;
DO WHILE (I >= 1);
I = I - 1;
PUT (I);
END;

4. CORRECT TEXT
Given the following declarations, which code is always a valid way to test if the value of B is 7?
DCL P POINTER NIT (NULL());
DCL B FIXED BIN (31) BASED (P);

A) IF P ^= NULL() ! B = 7
THEN PUT ('OK');
B) IF B = 7
THEN PUT ('OK');
C) IF B ^ = 7 THEN; ELSE
PUT ('OK');
D) IF ^ = NULL() THEN IF B = 7 THEN
PUT ('OK');

5. Given the following program, which subroutine improperly uses pointers to address memory and could lead to data corruption or an exception?

A) SUB4
B) SUB3
C) PROC OPTIONS(MAIN);
DCL
1 X,
2 X1 CHAR(76),
2 X2 PIC'9999';
DCL Y CHAR(20);
CALL SUB1( ADDR(X));
CALL SUB2( ADDR(X));
CALL SUB3( ADDR(X));
CALL SUB4( ADDR(X));
SUB 1: PROC( P);
DCL P POINTER;
DCL
1 XBASED(P),
2 X1 CHAR(76),
2 X2 PIC'9999'
X = ";
END;
SUB2: PROC( P);
DCL P POINTER;
DCL
1 X BASED(P),
2 X 1 PIC'(76)X'
2 X 2 PIC'9999'
X = ";
END;
SUB3: PROC( P);
DCL P POINTER;
DCL X CHAR(60) BASED(P);
X = ";
END;
SUB4: PROC( P );
DCL P POINTER;
DCLX CHAR(100) BASED(P);
X = ";
END; END;
D) SUB2
E) SUB1

Solutions: